Python Program to Check Leap Year

In this article, we've created some programs in Python, to check whether a year entered by user at run-time is a leap year or not. Here are the list of programs on checking leap year through Python:

• Simple Program to Check Leap Year or not
• Check Leap Year using Function
• Using Class

But before going through these programs, let's me clear the thing about leap year.

Condition for Leap Year

Any year can be called as a leap year, only if:

• either it is divided by 4, but not by 100
• or it is divided by 400

Note - If you're curious to understand about its logic, then refer to Leap Year Logic to get every required thing about it.

Check Leap Year

To check whether a given year is a leap year or not in Python, you have to ask from user to enter a year, then check and print the message whether it is a leap year or not as shown in the program given below. The question is, write a Python program to check whether a given year by user, is a leap year or not. Here is its answer:

print("Enter the Year: ")
y = int(input())

if y%4==0 and y%100!=0:
    print("\nIt is a Leap Year")
elif y%400==0:
    print("\nIt is a Leap Year")
else:
    print("\nIt is not a Leap Year")

Here is the initial output produced by this Python program:

Now supply the input say 2012 as year and press ENTER key to check whether it is a leap year or not, and print the message as shown in the snapshot given below:

Here is another sample run with user input, 1900 as year:

Modified Version of Previous Program

This is the modified version of previous program. Here we've used end, that skips printing of an automatic newline using print(). The method, str() is used to convert any type of value to a string type, so that all the string inside print() gets concatenated using + operator:

print("Enter the Year: ", end="")
y = int(input())

if y%4==0 and y%100!=0:
    print("\n" +str(y)+ " is a Leap Year")
elif y%400==0:
    print("\n" +str(y)+ " is a Leap Year")
else:
    print("\n" +str(y)+ " is not a Leap Year")

Here is its sample run with user input, 2000:

Check Leap Year using Function

This program does the same job as of previous program. The only difference is, this program uses a user-defined function named checkLeapOrNot(). This function receives year's value entered by user as its argument. It returns 1 if year is a leap year.

def checkLeapOrNot(x):
    if y % 4 == 0 and y % 100 != 0:
        return 1
    elif y % 400 == 0:
        return 1

print("Enter the Year: ", end="")
y = int(input())

chk = checkLeapOrNot(y)
if chk==1:
    print("\n" +str(y)+ " is a Leap Year")
else:
    print("\n" +str(y)+ " is not a Leap Year")

This program produces similar output as of previous program.

Check Leap Year using Class

This program uses class named fresherearth, an object-oriented feature of Python to do the same job as of previous program. Since to access any member function of the class, we've to use its object. Therefore we've created an object named ob. Let's have a look at the program given below to understand in better way:

class fresherearth:
    def checkLeapOrNot(self, x):
        if y % 4 == 0 and y % 100 != 0:
            return 1
        elif y % 400 == 0:
            return 1

print("Enter the Year: ", end="")
y = int(input())

ob = fresherearth()
chk = ob.checkLeapOrNot(y)
if chk==1:
    print("\nLeap Year")
else:
    print("\nNot a Leap Year")

Here is its sample run with user input 2014:

Same Program in Other Languages

• Java Check Leap Year or Not
• C Check Leap Year or Not
• C++ Check Leap Year or Not

Python Online Test