C++ Program to Find and Print Even Numbers in an Array

This article is created to cover some programs in C++ that find and print even numbers in an array. The array must be entered by the user at run-time. The list of programs covered in this article is as follows:

Print even numbers in an array of 10 elements

The question is: create a C++ program that prints even numbers from an array supplied by the user. The answer to this question is the program given below:

#include<iostream>

using namespace std;
int main()
{
   int arr[10], i;
   cout<<"Enter any 10 numbers: ";
   for(i=0; i<10; i++)
      cin>>arr[i];
   cout<<"\nEven Numbers are:\n";
   for(i=0; i<10; i++)
   {
      if(arr[i]%2==0)
         cout<<arr[i]<<" ";
   }
   cout<<endl;
   return 0;
}

The initial output produced by the above C++ program on printing all even numbers available in a given array is shown in the snapshot given below:

c++ program print even numbers in an array

Now enter any ten numbers, such as 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, and press the ENTER key to find and print all the even numbers, as shown in the screenshot below:

print even numbers in array c++

The following is the dry run of the above program with the exact same user input as provided above:

Print even numbers in an array of n numbers

Now let's modify the above program and create a new one that allows the user to define the size of the array. Also, this program prints a message if no even numbers are found.

#include<iostream>

using namespace std;
int main()
{
   int n, i, temp=0;
   cout<<"Enter the size of array: ";
   cin>>n;
   int arr[n];
   cout<<"Enter any "<<n<<" numbers: ";
   for(i=0; i<n; i++)
      cin>>arr[i];
   for(i=0; i<n; i++)
   {
      if(arr[i]%2==0)
      {
         if(temp==0)
            cout<<"\nEven Numbers are:\n";
         cout<<arr[i]<<" ";
         temp=1;
      }
   }
   if(temp==0)
      cout<<"\nEven number not found!";
   cout<<endl;
   return 0;
}

A sample run of the above program with user input of size 4 and 1, 3, 5, 7 as four numbers is shown below:

find even numbers in array c++ program

Here is another sample run with user input of 6 as size and 11, 22, 33, 44, 55, and 66 as six numbers for the array:

c++ find even numbers in array

Print even numbers in an array using another array

This program uses another array that stores all the even numbers from the array given by the user. After storing all even numbers from the given array in the second (another) array one by one, Just print the elements of the second array as shown in the program given below:

#include<iostream>

using namespace std;
int main()
{
   int n, i, j=0;
   cout<<"Enter the size of array: ";
   cin>>n;
   int arr[n], eve[n];
   cout<<"Enter any "<<n<<" numbers: ";
   for(i=0; i<n; i++)
   {
      cin>>arr[i];
      if(arr[i]%2==0)
      {
         eve[j] = arr[i];
         j++;
      }
   }
   if(j==0)
      cout<<"\nEven number not found!";
   else if(j==1)
      cout<<"\nThere is only 1 even number found. That is:\n"<<eve[0];
   else
   {
      cout<<"\nList of Even Numbers:\n";
      for(i=0; i<j; i++)
         cout<<eve[i]<<" ";
   }
   cout<<endl;
   return 0;
}

Here is its sample run with user input of 3 as size and 11, 22, and 33 as three numbers:

print even numbers from array c++

C++ Quiz


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